Compare this to log1p (which is its inverse).
Also, You may have to use a similar workaraound in case the underlying C library
does not support expm1:
function expm1($x) {
return ($x>-1.0e-6 && $x<1.0e-6) ? ($x + $x*$x/2) : (exp($x)-1);
}
expm1
(PHP 4 >= 4.0.7, PHP 5)
expm1 — 返回 exp(number) - 1,甚至当 number 的值接近零也能计算出准确结果
expm1
hagen at von-eitzen dot de
24-Feb-2003 07:57
24-Feb-2003 07:57
