PHP
downloads | documentation | faq | getting help | mailing lists | reporting bugs | php.net sites | links | conferences | my php.net

search for in the

mysql_field_type> <mysql_field_seek
Last updated: Mon, 26 Nov 2007

view this page in

mysql_field_table

(PHP 4, PHP 5, PECL mysql:1.0)

mysql_field_table — 取得指定字段所在的表名

说明

string mysql_field_table ( resource $result , int $field_offset )

返回指定字段所在的表的名字。

为向下兼容仍然可以使用 mysql_fieldtable(),但反对这样做。



mysql_field_type> <mysql_field_seek
Last updated: Mon, 26 Nov 2007
 
add a note add a note User Contributed Notes
mysql_field_table
PoMdaPiMp
25-Sep-2007 07:49
In the official example, there is a mistake.

<?php

[...]

$table = mysql_field_table($result, 'name');

[...]

?>

The last argument is here a string and not the integer expected by the function.
Indeed, in the synopsis, the two arguments' types are : result and integer.

Here is an other little example that corrects the mistake and give another use of the function.

<?php

// Build a very easy request
$query = "SELECT account.*, country.* FROM account, country WHERE country.name LIKE  '%france%' AND account.country_id = country.id";

// Gets the result from the DB
$result = mysql_query($query);

// Lists the table name and then the field name
for ($x = 0; $x < mysql_num_fields($result); $x++)
{
   
$str = mysql_field_name($result, $x);
    print (
'<b>' . mysql_field_table($result, $x) . '</b>: ' . $str . '<br />');
}

?>

In this little code, the offset is given to mysql_field_name as the second argument.
jorge at rhst dot net
30-Jul-2007 05:57
The function below takes a function and returns the col->table mapping as an array.

For example:

$query = “SELECT a.id AS a_id, b.id b_id FROM atable AS a, btable b”

$cols  = queryAlias($query);

print_r($cols);

Returns:

Array
(
    [a] => atable
    [b] => btable
)

I can't promise it's perfect, but this function never hit production cause I ended up using mysqli methods instead.

Enjoy
-Jorge

  /**
   * Takes in a query and returns the alias->table mapping.
   *
   * @param string $query
   * @return array of alias mapping
   */
 
  function queryAlias ( $query ) {
   
    //Make it all lower, we ignore case
    $substr = strtolower($query);
   
    //Remove any subselects
    $substr = preg_replace ( ‘/\(.*\)/’, ”, $substr);
  
    //Remove any special charactors
    $substr = preg_replace ( ‘/[^a-zA-Z0-9_,]/’, ‘ ‘, $substr);
   
    //Remove any white space
    $substr = preg_replace(‘/\s\s+/’, ‘ ‘, $substr);
   
    //Get everything after FROM
    $substr = strtolower(substr($substr, strpos(strtolower($substr),‘ from ‘) + 6));
   
    //Rid of any extra commands
    $substr = preg_replace(
                Array(
                    ‘/ where .*+$/’,
                    ‘/ group by .*+$/’,
                    ‘/ limit .*+$/’ ,
                    ‘/ having .*+$/’ ,
                    ‘/ order by .*+$/’,
                    ‘/ into .*+$/’
                   ), ”, $substr);
   
    //Remove any JOIN modifiers
    $substr = preg_replace(
                Array(
                    ‘/ left /’,
                    ‘/ right /’,
                    ‘/ inner /’,
                    ‘/ cross /’,
                    ‘/ outer /’,
                    ‘/ natural /’,
                    ‘/ as /’
                   ), ‘ ‘, $substr);
   
    //Replace JOIN statements with commas
    $substr = preg_replace(Array(‘/ join /’, ‘/ straight_join /’), ‘,’, $substr);
   

    $out_array = Array();
   
    //Split by FROM statements
    $st_array = split (‘,’, $substr);
 
    foreach ($st_array as $col) {
     
      $col = preg_replace(Array(‘/ on .*+/’), ”, $col);
     
      $tmp_array = split(‘ ‘, trim($col));
     
      //Oh no, something is wrong, let’s just continue
      if (!isset($tmp_array[0]))
        continue;
       
      $first = $tmp_array[0];
     
      //If the “AS” is set, lets include that, if not, well, guess this table isn’t aliased.
      if (isset($tmp_array[1]))
        $second = $tmp_array[1];
        else 
        $second = $first;
       
      if (strlen($first))
       $out_array[$second] = $first;
     
    }
   
    return $out_array;
  }
spam at blondella dot de
03-Oct-2006 07:09
<?php
/*
this function might help in the case described above :-)
*/
function mysql_field_table_resolve_alias($inQuery,$inResult,$inFieldName) {
  
$theNameOrAlias = mysql_field_table($inResult,$inFieldName);
  
//check, if AS syntax is being used
  
if(ereg(" AS ",$inQuery))  {
     
//catch words in query
     
$theWords = explode(" ",ereg_replace(",|\n"," ",$inQuery));
     
//find the words preceding and following AS
     
foreach($theWords as $theIndex => $theWord)  {
         if(
trim($theWord) == "AS"
        
&& isset($theWords[$theIndex-1])
         && isset(
$theWords[$theIndex+1])
         &&
$theWords[$theIndex+1] == $theNameOrAlias
        
) {
           
$theNameOrAlias = $theWords[$theIndex-1];
            break
1;
         }
      }
   }
   return
$theNameOrAlias;
}
?>
me at thomaskeller dot biz
24-Nov-2005 05:15
Beware that if you upgrade to MySQL 5 from any earlier version WITHOUT dumping and reloading your data (just by keeping the binary data in MyISAM table files), you might get weird output on the "table" value for mysql_fetch_field and in this function. Weird means that the table name is randomly set or not.

This behaviour seems to popup only if the SQL query contains a ORDER BY clause. A bug is already reported:

http://bugs.mysql.com/bug.php?id=14915

To prevent the issue, dump and reload all participating tables in your query or do

CREATE TABLE tmp SELECT * FROM table;
DROP TABLE table;
ALTER TABLE tmp RENAME table;

on each one via commandline client.
cptnemo
15-Aug-2004 10:18
When trying to find table names for a (My)SQL query containing 'tablename AS alias', mysql_field_table() only returns the alias as specified in the AS clause, and not the tablename.

mysql_field_type> <mysql_field_seek
Last updated: Mon, 26 Nov 2007
 
 
show source | credits | sitemap | contact | advertising | mirror sites