getdate

(PHP 4, PHP 5)

getdate — 取得日期／时间信息

说明

array getdate ([ int $timestamp ] )

返回一个根据 timestamp 得出的包含有日期信息的结合数组。如果没有给出时间戳则认为是当前本地时间。数组中的单元如下：

**返回的关联数组中的键名单元**
键名	说明	返回值例子
"seconds"	秒的数字表示	0 到 59
"minutes"	分钟的数字表示	0 到 59
"hours"	小时的数字表示	0 到 23
"mday"	月份中第几天的数字表示	1 到 31
"wday"	星期中第几天的数字表示	0（表示星期天）到 6（表示星期六）
"mon"	月份的数字表示	1 到 12
"year"	4 位数字表示的完整年份	例如：1999 或 2003
"yday"	一年中第几天的数字表示	0 到 365
"weekday"	星期几的完整文本表示	Sunday 到 Saturday
"month"	月份的完整文本表示	January> 到 December
0	自从 Unix 纪元开始至今的秒数，和 time() 的返回值以及用于 date() 的值类似。	系统相关，典型值为从 -2147483648 到 2147483647。

Example#1 getdate() 例子


<?php
$today = getdate();
print_r($today);
?>

上例的输出类似于：

Array
(
    [seconds] => 40
    [minutes] => 58
    [hours]   => 21
    [mday]    => 17
    [wday]    => 2
    [mon]     => 6
    [year]    => 2003
    [yday]    => 167
    [weekday] => Tuesday
    [month]   => June
    [0]       => 1055901520
)

参见 date()，time() 和 setlocale()。

gettimeofday

date

Last updated: Mon, 26 Nov 2007

add a note User Contributed Notes
getdate

chris AT cmbuckley DOT co DOT uk
08-Aug-2008 10:08


For those who want the gmgetdate function that matches the behaviour of getdate:



<?php

function gmgetdate($timestamp = null) {

    if (is_null($timestamp)) { $timestamp = time(); }



    $dateParts = array(

        'mday'    => 'j',

        'wday'    => 'w',

        'yday'    => 'z',

        'mon'     => 'n',

        'year'    => 'Y',

        'hours'   => 'G',

        'minutes' => 'i',

        'seconds' => 's',

        'weekday' => 'l',

        'month'   => 'F',

        0         => 'U'

    );



    while (list(, $value) = each($dateParts)) {

        $value = gmdate($value, $timestamp);

        if (is_numeric($value)) { $value = (int)$value; }

    }



    return $dateParts;

}

?>

timforte at gmail dot com
11-Jan-2008 12:07


It's worth noting that this is local time, not UTC/GMT - gmgetdate doesn't exist :(.





The most logical way to handle date arithmetic without hitting DST problems is to work in UTC...





<?php


function add_days($my_date,$numdays) {


  $date_t = strtotime($my_date.' UTC');


  return gmdate('Y-m-d',$date_t + ($numdays*86400));


}


?>





[it's even faster if you use gmmktime instead of strtotime]

andre at anlex dot co dot za
13-Dec-2006 08:38


I thought best to show a posseble way to go about bypassing the end month issue where the first day in a new month will have the monday of the week that it falls in - in the old month. Use the numbering of days as the constant and work you way from there.



Example:

<?php

//-----------------------------

$now = time();

$num = date("w");

if ($num == 0)

{ $sub = 6; }

else { $sub = ($num-1); }

$WeekMon  = mktime(0, 0, 0, date("m", $now)  , date("d", $now)-$sub, date("Y", $now));    //monday week begin calculation

$todayh = getdate($WeekMon); //monday week begin reconvert



$d = $todayh[mday];

$m = $todayh[mon];

$y = $todayh[year];

echo "$d-$m-$y"; //getdate converted day



?> 



Allot less code makes everyone happy..

Jared Armstrong
10-Dec-2006 02:05


A nice little function I wrote to determine what number occurrence weekday it is of the month for a given timestamp. (I.e. 2nd Friday, or the 3rd Thursday)





Eg: print_r(getWeekdayOccurrence(mktime(0, 0, 0, 12, 1, 2006)));


Outputs: Array ( [0] => 1 [1] => Friday )  [The first friday]





Eg. print_r(getWeekdayOccurrence(mktime(0, 0, 0, 8, 17, 2009)));


Outputs: Array ( [0] => 3 [1] => Monday ) [The third Monday]





<?php


function getWeekdayOccurrence($time) { 


    $month = intval(date("m", $time)); $day = intval(date("d", $time));


    for ($i = 0; $i < 7; $i++) {


        $days[] = date("l", mktime(0, 0, 0, $month, ($i+1), date("Y", $time)));    


    }





    $posd  = array_search(date("l", $time), $days);


    $posdm = array_search($days[0], $days) - $posd; /





    return array((($day+$posdm+6)/7), $days[$posd]);        


}


?>

cesar at nixar dot org
22-Oct-2006 11:49


<?php



  /**

   *  This function is similar to getdate() but it returns

   * the month information.

   *

   *  Returns an associative array containing the month

   * information of the parameters, or the current month

   * if no parameters are given.

   *

   */



  function getmonth ($month = null, $year = null)

  {

      // The current month is used if none is supplied.

      if (is_null($month))

          $month = date('n');



      // The current year is used if none is supplied.

      if (is_null($year))

          $year = date('Y');



      // Verifying if the month exist

      if (!checkdate($month, 1, $year))

          return null;



      // Calculating the days of the month

      $first_of_month = mktime(0, 0, 0, $month, 1, $year);

      $days_in_month = date('t', $first_of_month);

      $last_of_month = mktime(0, 0, 0, $month, $days_in_month, $year);



      $m = array();

      $m['first_mday'] = 1;

      $m['first_wday'] = date('w', $first_of_month);

      $m['first_weekday'] = strftime('%A', $first_of_month);

      $m['first_yday'] = date('z', $first_of_month);

      $m['first_week'] = date('W', $first_of_month);

      $m['last_mday'] = $days_in_month;

      $m['last_wday'] = date('w', $last_of_month);

      $m['last_weekday'] = strftime('%A', $last_of_month);

      $m['last_yday'] = date('z', $last_of_month);

      $m['last_week'] = date('W', $last_of_month);

      $m['mon'] = $month;

      $m['month'] = strftime('%B', $first_of_month);

      $m['year'] = $year;



      return $m;

  }



  // Output

  print_r(getmonth(11, 1978));

  print_r(getmonth());



?>

Cas_AT_NUY_DOT_INFO
04-Mar-2006 09:47


<?php


// This functions calculates the next date only using business days


// 2 parameters, the startdate and the number of businessdays to add


    function calcduedate($datecalc,$duedays) {


    $i = 1;


    while ($i <= $duedays) {


        $datecalc += 86400; // Add a day.


        $date_info  = getdate( $datecalc );


        if (($date_info["wday"] == 0) or ($date_info["wday"] == 6) )  {


            $datecalc += 86400; // Add a day.


            continue;


        }


        $i++;


    }


    return $datecalc ;


    }


?>

leo25in at yahoo dot com
11-May-2005 08:17


getting weekday(actual date) from any give date.





<?php


function cal_date($wday,$tstamp)


{


    return $tstamp-($wday*(24*3600));


}





function getweekday($m,$d,$y)


{


    $tstamp=mktime(0,0,0,$m,$d,$y);


    


    $Tdate = getdate($tstamp);


    


    $wday=$Tdate["wday"];


    


    switch($wday)


    {


        case 0;


        $wstamp=cal_date($wday,$tstamp);


        //echo date("Y-m-d",$wstamp);


        break;


        


        case 1;


        $wstamp=cal_date($wday,$tstamp);


        //echo date("Y-m-d",$wstamp);


        break;


        


        


        case 2;


        $wstamp=cal_date($wday,$tstamp);


        //echo date("Y-m-d",$wstamp);


        break;


        


        case 3;


        $wstamp=cal_date($wday,$tstamp);


        //echo date("Y-m-d",$wstamp);


        break;


        


        case 4;


        $wstamp=cal_date($wday,$tstamp);


        //echo date("Y-m-d",$wstamp);


        break;


        


        case 5;


        $wstamp=cal_date($wday,$tstamp);


        //echo date("Y-m-d",$wstamp);


        break;


        


        case 6;


        $wstamp=cal_date($wday,$tstamp);


        //echo date("Y-m-d",$wstamp);


        break;


    }


    


    


     $w["day"]=date("d",$wstamp);


     $w["month"]=date("m",$wstamp);


     $w["year"]=date("Y",$wstamp);


     


     return $w;





}


?>

getisomonday($year, $week)
22-Apr-2004 05:58


getdate does not convert week numbers. this function relies on strftime to find a timestamp that falls on the monday of specified year and ISO week:



<?php function getisomonday($year, $week) {

        # check input

        $year = min ($year, 2038); $year = max ($year, 1970);

        $week = min ($week, 53); $week = max ($week, 1);

        # make a guess

        $monday = mktime (1,1,1,1,7*$week,$year);

        # count down to week

        while (strftime('%V', $monday) != $week)

                $monday -= 60*60*24*7;

        # count down to monday

        while (strftime('%u', $monday) != 1)

                $monday -= 60*60*24;

        # got it

        return $monday;

} ?>

Yura Pylypenko (plyrvt at mail dot ru)
15-Sep-2003 09:29


In addition to canby23 at ms19 post:

It's a very bad idea to consider day having 24 hours (86400 secs), because some days have 23, some - 25 hours due to daylight saving changes. Using of mkdate() and strtotime() is always preferred. strtotime() also has a very nice behaviour of datetime manipulations:

<?php

echo strtotime ("+1 day"), "\n";

echo strtotime ("+1 week"), "\n";

echo strtotime ("+1 week 2 days 4 hours 2 seconds"), "\n";

echo strtotime ("next Thursday"), "\n";

echo strtotime ("last Monday"), "\n"; 

?>

add a note

gettimeofday

date

Last updated: Mon, 26 Nov 2007