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array_unique> <array_uintersect_uassoc
Last updated: Mon, 26 Nov 2007

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array_uintersect

(PHP 5)

array_uintersect — 计算数组的交集,用回调函数比较数据

说明

array array_uintersect ( array $array1 , array $array2 [, array $ ... ], callback $data_compare_func )

array_uintersect() 返回一个数组,该数组包含了所有在 array1 中也同时出现在所有其它参数数组中的值。数据比较是用回调函数进行的。

Example#1 array_uintersect() 例子

<?php
$array1 
= array("a" => "green""b" => "brown""c" => "blue""red");
$array2 = array("a" => "GREEN""B" => "brown""yellow""red");

print_r(array_uintersect($array1$array2"strcasecmp"));
?>

上例将输出:

Array
(
    [a] => green
    [b] => brown
    [0] => red
)

此比较是通过用户提供的回调函数来进行的。如果认为第一个参数小于,等于,或大于第二个参数时必须分别返回一个小于零,等于零,或大于零的整数。

参见 array_intersect()array_uintersect_assoc()array_intersect_uassoc()array_uintersect_uassoc()



add a note add a note User Contributed Notes
array_uintersect
Nate at RuggFamily dot com
03-Feb-2007 04:03
I want to stress that in the user function, you do need to return either a 1 or a -1 properly; you cannot simply return 0 if the results are equal and 1 if they are not. 

The following code is incorrect:

<?php
function myfunction($v1,$v2)
{
if (
$v1===$v2)
    {
    return
0;
    }
return
1;
}

$a1=array(1, 2, 4);
$a2=array(1, 3, 4);
print_r(array_uintersect($a1,$a2,"myfunction"));
?>

This code is correct:

<?php
function myfunction($v1,$v2)
{
if (
$v1===$v2)
    {
    return
0;
    }
if (
$v1 > $v2) return 1;
return -
1;
}
$a1=array(1, 2, 4);
$a2=array(1, 3, 4);
print_r(array_uintersect($a1,$a2,"myfunction"));
?>

array_unique> <array_uintersect_uassoc
Last updated: Mon, 26 Nov 2007
 
 
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